How much charge is stored in a 0.022 $\mu \mathrm { F }$ capacitor that drops 22 V?
A) 4.84 $\mu \mathrm { C }$
B) 0.484 $\mu \mathrm { C }$
C) 48.4 $\mu \mathrm { C }$
D) 0.0484 $\mu \mathrm { C }$

Question

How much charge is stored in a  0.022  $\mu \mathrm { F }$ capacitor that drops 22 V?
A)  4.84  $\mu \mathrm { C }$
B)  0.484  $\mu \mathrm { C }$
C)  48.4  $\mu \mathrm { C }$
D)  0.0484  $\mu \mathrm { C }$

Quizplus · Accepted Answer

The charge stored in a capacitor is given by:

$$Q = CV$$

where Q is the charge stored, C is the capacitance, and V is the potential difference (voltage) across the capacitor.

Substituting the given values, we get:

$$Q = (0.022 \mu F)(22 V) = 0.484 \mu C$$

Therefore, the answer is B.

How Much Charge Is Stored in a 0 μF\mu \mathrm { F }μF

How Much Charge Is Stored in a 0 $\mu \mathrm { F }$