How much voltage is dropped across a 150 $\mu \mathrm { F }$ capacitor after 3.33 seconds if it is charged by a 50 V source through a 22 $\mathrm { K } \Omega$ resistor?
A) 49 V
B) 31.8 V
C) 43.3 V
D) 47.5 V

Question

How much voltage is dropped across a 150 $\mu \mathrm { F }$ capacitor after  3.33  seconds if it is charged by a  50 V source through a 22 $\mathrm { K } \Omega$ resistor?
A)  49  V
B)  31.8  V
C)  43.3  V
D)  47.5  V

Quizplus · Accepted Answer

The voltage across a capacitor in a charging circuit can be calculated using the formula:
V = V0(1 - e^(-t/RC))
where V0 is the initial voltage, t is the time, R is the resistance, and C is the capacitance.
Plugging in the values given in the problem, we get:
V = 50(1 - e^(-3.33/(22*10^3*150*10^-6)))
V ≈ 31.8 V
Therefore, the voltage dropped across the capacitor is approximately 31.8 V, so the correct answer is B.

How Much Voltage Is Dropped Across a 150 μF\mu \mathrm { F }μF

How Much Voltage Is Dropped Across a 150 $\mu \mathrm { F }$