$$\text { Figure } 6 ^ { \prime } 2$$ -If V_S=15 V and every resistor equals 2.2 $k \Omega$ in Figure 6-2, what is the value of I_R4 ? A) 5.11 mA B) 2.55 mA C) 0.85 mA D) 0.42 mA

Question

Quizplus · Accepted Answer

Using voltage division, the voltage across R4 is:VR4 = VS * R4 / (R1 + R2 + R3 + R4)= 15 V * 2.2 kΩ / (2.2 kΩ + 2.2 kΩ + 2.2 kΩ + 2.2 kΩ)= 5.11 VThe current through R4 is:IR4 = VR4 / R4= 5.11 V / 2.2 kΩ= 2.32 mA

Figure 6′2\text { Figure } 6 ^ { \prime } 2 Figure 6′2

$\text { Figure } 6 ^ { \prime } 2$