If a 470$\Omega$ resistor,680$\Omega$ resistor and 830$\Omega$ resistor are connected in parallel, the total resistance equals_______
A) 1980$\Omega$
B) 1150 $\Omega$
C) 208$\Omega$
D) 1510 $\Omega$

Question

If a  470$\Omega$  resistor,680$\Omega$  resistor and 830$\Omega$  resistor are connected in parallel, the total resistance equals_______
A)  1980$\Omega$
B) 1150 $\Omega$
C)  208$\Omega$
D) 1510 $\Omega$

Quizplus · Accepted Answer

The total resistance $R_{total}$ of resistors in parallel is given by $\frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}$. Plugging in the given values, $\frac{1}{R_{total}} = \frac{1}{470} + \frac{1}{680} + \frac{1}{830}$, which calculates to $R_{total} \approx 208\Omega$.

If a 470 Ω\OmegaΩ Resistor,680 Ω\OmegaΩ Resistor and 830 Ω\OmegaΩ Resistor Are Connected in Parallel, the Total Resistance Equals_______ A)

If a 470 $\Omega$ Resistor,680 $\Omega$ Resistor and 830 $\Omega$ Resistor Are Connected in Parallel, the Total Resistance Equals_______
A)