If three 4.7 $\mathrm { k } \Omega$ resistors are connected in parallel across a 12 V source, what is the value of P_T ? A) 141 mW B) 14.1 mW C) 91.9 mW D) 1.41 W

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Quizplus · Accepted Answer

When resistors are connected in parallel, the total resistance ($R_{total}$) is given by $\frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}$ for three resistors. For three 4.7 kΩ resistors in parallel, $R_{total} = \frac{4.7}{3}$ kΩ = 1.5667 kΩ. The power ($P$) dissipated can be calculated using $P = \frac{V^2}{R}$, where $V = 12V$. Thus, $P = \frac{12^2}{1.5667}$ W = 91.9 mW.

If Three 4 kΩ\mathrm { k } \OmegakΩ Resistors Are Connected in Parallel Across a 12 V

If Three 4 $\mathrm { k } \Omega$ Resistors Are Connected in Parallel Across a 12 V