If 6.8 $\mathrm { k } \Omega$, 1.2 $\mathrm { k } \Omega$ and 5.6 $\mathrm { k } \Omega$
resistors are wired in series, the total resistance is 13.6 $\mathrm { k } \Omega$

Question

If  6.8  $\mathrm { k } \Omega$,  1.2  $\mathrm { k } \Omega$ and  5.6  $\mathrm { k } \Omega$
 resistors are wired in series, the total resistance is  13.6  $\mathrm { k } \Omega$

Quizplus · Accepted Answer

When resistors are wired in series, their resistances add up. Therefore, $6.8 \, \mathrm{k}\Omega + 1.2 \, \mathrm{k}\Omega + 5.6 \, \mathrm{k}\Omega = 13.6 \, \mathrm{k}\Omega$.

If 68 kΩ\mathrm { k } \OmegakΩ , 12 kΩ\mathrm { k } \OmegakΩ

If 68 $\mathrm { k } \Omega$ , 12 $\mathrm { k } \Omega$