If 4.7 $\mathrm { k } \Omega$
, 2.2 $\mathrm { k } \Omega$ and 1.2 $\mathrm { k } \Omega$ resistors are wired in series, the total resistance is 8.7 $\mathrm { k } \Omega \text {. }$

Question

If  4.7 $\mathrm { k } \Omega$
, 2.2 $\mathrm { k } \Omega$ and  1.2 $\mathrm { k } \Omega$  resistors are wired in series, the total resistance is  8.7 $\mathrm { k } \Omega \text {. }$

Quizplus · Accepted Answer

When resistors are wired in series, their individual resistances add up to give the total resistance. Therefore, the total resistance in this scenario would be 4.7 kΩ + 2.2 kΩ + 1.2 kΩ = 8.1 kΩ, not 8.7 kΩ.

If 47 kΩ\mathrm { k } \OmegakΩ , 22 kΩ\mathrm { k } \OmegakΩ

If 47 $\mathrm { k } \Omega$ , 22 $\mathrm { k } \Omega$