In a series circuit, total power P_T is calculated as: A) $\mathrm { P } _ { 1 } + \mathrm { P } _ { 2 } + \mathrm { P } _ { 3 } + \text { etc. }$ B) $\mathrm { P } _ { 1 } \times \mathrm { P } _ { 2 } \times \mathrm { P } _ { 3 } \times \text { etc. }$ C) $1 / \mathrm { P } _ { 1 } + 1 / \mathrm { P } _ { 2 } + 1 / \mathrm { P } _ { 3 } + \mathrm { etc }$ D) $\mathrm { P } _ { 1 } \div \mathrm { P } _ { 2 } \div \mathrm { P } _ { 3 } \div \text { etc. }$

Question

Quizplus · Accepted Answer

In a series circuit, the current through each component is the same and the total resistance is the sum of the individual resistances. Therefore, the total power is calculated by adding up the power of each individual component, which is given by P = V * I, where V is the voltage across the component and I is the current flowing through it. Hence, the correct option is A: P1 + P2 + P3 + etc.

In a Series Circuit, Total Power PT Is Calculated P1+P2+P3+ etc. \mathrm { P } _ { 1 } + \mathrm { P } _ { 2 } + \mathrm { P } _ { 3 } + \text { etc. }P1​+P2​+P3​+ etc.

In a Series Circuit, Total Power P_T Is Calculated $\mathrm { P } _ { 1 } + \mathrm { P } _ { 2 } + \mathrm { P } _ { 3 } + \text { etc. }$