$$\text { Figure } 19

Question

$$\text { Figure } 19 < 3$$
-If  R=47  $\mathrm { k } \Omega$ and  C=0.02 $\mu \mathrm { F }$  in Figure 19-3, $\mathrm { fCO }$ equals______
A) 5.19 Hz 
B) 16.9 Hz 
C) 169 Hz 
D) 51.9 Hz

Quizplus · Accepted Answer

The cutoff frequency ($f_{CO}$) for a low-pass or high-pass RC filter is given by the formula $f_{CO} = \frac{1}{2\pi RC}$, where $R$ is the resistance in ohms ($\Omega$), $C$ is the capacitance in farads (F), $f_{CO}$ is the cutoff frequency in hertz (Hz), and $\pi \approx 3.14159$. Given $R = 47 \times 10^3 \Omega$ (since $1 k\Omega = 1000 \Omega$) and $C = 0.02 \times 10^{-6} F$ (since $1 \mu F = 10^{-6} F$), substituting these values into the formula gives $f_{CO} = \frac{1}{2\pi \times 47 \times 10^3 \times 0.02 \times 10^{-6}} \approx 169 Hz$.

Figure 19<3\text { Figure } 19 < 3 Figure 19<3 -If R=47 kΩ\mathrm { k } \OmegakΩ

$\text { Figure } 19 < 3$ -If R=47 $\mathrm { k } \Omega$