If $\mathrm { R } _ { \mathrm { i } } = 2.2 \mathrm { k } \Omega , \mathrm { R } _ { f } = 220 \mathrm { k } \Omega$ and A_OL=25,000 in an inverting op-amp, ACL equals_______ A) -250 B) -0.01 C) 100 D) -100

Question

Quizplus · Accepted Answer

ACL is the closed-loop gain of the inverting amplifier and is given by the formula:

$$
A_{CL}=-\frac{R_f}{R_i}
$$

Substituting the given values, we get:

$$
A_{CL}=-\frac{220\mathrm{k}\Omega}{2.2\mathrm{k}\Omega}=-100
$$

Therefore, the answer is D) -100.

If Ri=2.2kΩ,Rf=220kΩ\mathrm { R } _ { \mathrm { i } } = 2.2 \mathrm { k } \Omega , \mathrm { R } _ { f } = 220 \mathrm { k } \OmegaRi​=2.2kΩ,Rf​=220kΩ

If $\mathrm { R } _ { \mathrm { i } } = 2.2 \mathrm { k } \Omega , \mathrm { R } _ { f } = 220 \mathrm { k } \Omega$