What is V_C at the end of the input pulse to an R_C integrator if the input pulse is 12 V and the pulse width equals one time constant? A) 7.59 V B) 4.41 V C) 12 V D) 0 V

Question

Quizplus · Accepted Answer

For an RS flip-flop integrator, the output voltage at the end of an input pulse that equals one time constant is given by $V_{out} = V_{in}(1 - e^{-1})$, where $e$ is the base of the natural logarithm (approximately 2.71828). Substituting $V_{in} = 12V$, we get $V_{out} = 12V(1 - e^{-1}) \approx 12V(1 - 1/2.71828) \approx 12V(0.632) = 7.584V$, which rounds to 7.59 V.

What Is VC at the End of the Input

What Is V_C at the End of the Input