What is one time constant for a 10 mH inductor connected in series with a 47 $\mathrm { k } \Omega$ resistor?
A) 0.213 $\mu S$
B) 470 mS
C) 213 $\mu S$
D) 470 S

Question

What is one time constant for a  10 mH inductor connected in series with a 47 $\mathrm { k } \Omega$ resistor?
A)  0.213  $\mu S$
B)  470 mS
C) 213 $\mu S$
D)  470 S

Quizplus · Accepted Answer

The time constant for an inductor-resistor circuit is given by the product of the inductance and the resistance. In this case, the inductance is 10 mH and the resistance is 47 kΩ, so the time constant is:$$ 	au = L 	imes R = 10 	ext{ mH} 	imes 47 	ext{ k}\Omega = 0.213 \mu 	ext{S} $$

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