If a 50 mH inductor is in series with a 50 $\mathrm { k } \Omega$ resistor across a 50 V_DC source, what is the maximum current that will flow in the circuit? A) 1 $\mu \mathrm { A }$ B) 10 mA C) 100 $\mu \mathrm { A }$ D) 1 mA

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Quizplus · Accepted Answer

The maximum current in a DC circuit is determined by Ohm's Law, $ I = \frac{V}{R} $. Here, $ V = 50 \, V $ and $ R = 50 \, k\Omega $, so $ I = \frac{50}{50,000} = 0.001 \, A = 1 \, mA $. The inductor does not affect the maximum steady-state current in a DC circuit.

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