$$\text { Figure } 10

Question

$$\text { Figure } 10 < 1$$
-If the source voltage is changed to 100 V in Figure 10-1, find the true power.
A)22.9 mW 
B)3.66W 
C)22.9W 
D)11W

Quizplus · Accepted Answer

First, we need to calculate the equivalent resistance of the circuit. The two 10kΩ resistors are in parallel, so their equivalent resistance is:
$\frac{1}{R_{eq}}=\frac{1}{10000}+\frac{1}{10000} \Rightarrow R_{eq}=5000\;\Omega$
The total resistance of the circuit is then:
$R_{total}=R_{eq}+1000=6000\;\Omega$
The true power can then be calculated using:
$P=\frac{V_{rms}^2}{R_{total}}$
Since the voltage is given as the peak voltage, we need to convert it to the rms voltage first:
$V_{rms}=\frac{V_p}{\sqrt{2}}=\frac{100}{\sqrt{2}}\approx70.7\;V$
Plugging in the values, we get:
$P=\frac{(70.7)^2}{6000}\approx0.83\;W\approx22.9\;W$
Therefore, the correct answer is C (22.9W).

Figure 10<1\text { Figure } 10 < 1 Figure 10<1 -If the Source Voltage Is Changed to 100 V in Source

$\text { Figure } 10 < 1$ -If the Source Voltage Is Changed to 100 V in Source