The Pitman arm on a car costs $105 to repair. Compute the quality loss function for losses incurred as a result of deviation from a target where a tolerance of 10 plus or minus 0.2 is required and the mean squared deviation (V)from the target is (0.05)2.

Question

Quizplus · Accepted Answer

The quality loss function is given by: 
QL = (C×V)² 
where C is the cost of deviation from the target and V is the mean squared deviation. 
For this problem, C = $105 (cost to repair) and V = (0.05)² = 0.0025 (given). 
The tolerance is 10 ±0.2, which means the target value is 10 and any deviation from this target between 9.8 and 10.2 is acceptable. 
Thus, the quality loss for a deviation of 0.2 from the target is: 
QL = (105 × 0.0025)² = $6.56 
Therefore, the best choice is B as it corresponds to the calculated quality loss.

The Pitman Arm on a Car Costs $105 to Repair