How many grams of are there in 0.500 mole of
A) 160 g
B) 79.9 g
C) 63.8 g
D) 51.9 g
E) 35.9 g

Question

How many grams of  are there in  0.500  mole of 
A) 160 g 
B) 79.9 g 
C) 63.8 g 
D) 51.9 g 
E) 35.9 g

Quizplus · Accepted Answer

To solve this problem, we need to use Avogadro's number and the molar mass of 11ec7dc6_5d6e_7818_8044_1b3b06f3222f_TB34225555_11.

Molar Mass of 11ec7dc6_5d6e_7818_8044_1b3b06f3222f_TB34225555_11 = 342.3 g/mol

Number of moles of 11ec7dc6_5d71_ac69_8044_3d6295e55a39_TB34225555_11 = 0.500 moles

Number of molecules of 11ec7dc6_5d71_ac69_8044_3d6295e55a39_TB34225555_11 = 0.500 x Avogadro's number

Number of grams of 11ec7dc6_5d71_ac69_8044_3d6295e55a39_TB34225555_11 = Number of moles x Molar Mass

Number of grams of 11ec7dc6_5d71_ac69_8044_3d6295e55a39_TB34225555_11 = 0.500 x 342.3 g/mol

Number of grams of 11ec7dc6_5d71_ac69_8044_3d6295e55a39_TB34225555_11 = 171.15 g

Now we can use stoichiometry to find how many grams of 11ec7dc6_5d6e_7818_8044_1b3b06f3222f_TB34225555_11 are in 171.15 g of 11ec7dc6_5d71_ac69_8044_3d6295e55a39_TB34225555_11.

1 mole of 11ec7dc6_5d71_ac69_8044_3d6295e55a39_TB34225555_11 contains 1 mole of 11ec7dc6_5d6e_7818_8044_1b3b06f3222f_TB34225555_11

Number of moles of 11ec7dc6_5d71_ac69_8044_3d6295e55a39_TB34225555_11 = 0.500 moles

Number of moles of 11ec7dc6_5d6e_7818_8044_1b3b06f3222f_TB34225555_11 = 0.500 moles

Number of grams of 11ec7dc6_5d6e_7818_8044_1b3b06f3222f_TB34225555_11 = Number of moles x Molar Mass

Number of grams of 11ec7dc6_5d6e_7818_8044_1b3b06f3222f_TB34225555_11 = 0.500 x 342.3 g/mol

Number of grams of 11ec7dc6_5d6e_7818_8044_1b3b06f3222f_TB34225555_11 = 171.15 g x (1/342.3)

Number of grams of 11ec7dc6_5d6e_7818_8044_1b3b06f3222f_TB34225555_11 = 0.4996 g

The answer is B (79.9 g) which is the closest to the calculated value of 0.4996 g.

How Many Grams of Are There in 0