How many milliliters of 0.400 M NaOH are required to completely neutralize 20.0 mL of 0.200 M HCl?
A)10.0 mL
B)50.0 mL
C)0.100 mL
D)40.0 mL
E)20.0 mL

Question

Quizplus · Accepted Answer

The correct answer is A because the number of moles of NaOH required to neutralize the HCl is equal to the number of moles of HCl present. The number of moles of HCl is 20.0 mL * 0.200 M = 0.00400 mol. Therefore, the number of moles of NaOH required is also 0.00400 mol. The volume of 0.400 M NaOH required to provide 0.00400 mol of NaOH is 0.00400 mol / 0.400 M = 10.0 mL.

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