Figure 12-18 A delta-connected alternator is connected to a wye-connected resistive load. The alternator produces a line voltage of 240 V and the resistors have a value of 6 ohms each. Find the specified values:
-IL(Load) = ____ A.
A) 23.1
B) 24.2
C) 25.3
D) 26.4

Question

Figure 12-18  A delta-connected alternator is connected to a wye-connected resistive load. The alternator produces a line voltage of 240 V and the resistors have a value of 6 ohms each. Find the specified values:
-IL(Load) = ____ A.
A) 23.1 
B) 24.2 
C) 25.3 
D) 26.4

Quizplus · Accepted Answer

Since the alternator is delta-connected and the load is wye-connected, the line current (IL) in the load is equal to the phase current (Iph) in the alternator.

The phase voltage (Vph) in the alternator is equal to the line voltage (Vline), so:

Vph = Vline = 240 V

The impedance of each resistor in the load is equal to its resistance (R), so:

Z = R = 6 ohms

The phase current in the alternator can be found using Ohm's law:

Iph = Vph/Z = 240/6 = 40 A

The line current in the load is equal to the sum of the phase currents:

IL = 3Iph = 3(40) = 120 A

Therefore, the answer is A) 23.1.

Figure 12-18 a Delta-Connected Alternator Is Connected to a Wye-Connected