Suppose Bohr had chosen the potential energy of the electron in the hydrogen atom to be V = 0 when the electron is in the orbit with n = 1. He could do this by
A) choosing n = 1 for the orbit where the kinetic energy of the electron is zero.
B) adding a constant 13.6 eV to the potential energy for all values of n.
C) adding a constant 27.2 eV to the potential energy for all values of n.
D) subtracting a constant 13.6 eV from the potential energy for all values of n.
E) subtracting a constant 27.2 eV from the potential energy for all values of n.
Correct Answer:
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