Assume electrons are accelerated through a potential difference of 25 000 V inside a TV picture tube.What is the minimum wavelength that could be produced when the electrons strike the phosphor? (1 Å = 10-10 m)
A)0.50 Å
B)1.0 Å
C)10 Å
D)100 Å
E)0.25 Å

Question

Quizplus · Accepted Answer

The minimum wavelength is given by the de Broglie wavelength, which is h/p, where h is Planck's constant and p is the momentum of the electron. The momentum of the electron is given by sqrt(2meV), where m is the mass of the electron, e is the charge of the electron, and V is the potential difference. Substituting these values into the de Broglie wavelength equation, we get:lambda = h/sqrt(2meV) = (6.626 x 10^-34 J s)/sqrt(2 * 9.109 x 10^-31 kg * 1.602 x 10^-19 C * 25000 V) = 5.0 x 10^-11 m = 0.50 Å

Assume Electrons Are Accelerated Through a Potential Difference of 25