In an X-ray diffraction experiment using X-rays of $\lambda$ = 0.500 *10-10 m, a first-order maximum occurred at 5.00$\degree$.Find the crystal plane spacing.
A)2.87 *10-10 m
B)1.36 *10-10 m
C)6.24 * 10-9 m
D)1.93 * 10-9 m
E)5.74 * 10-9 m

Question

Quizplus · Accepted Answer

The crystal plane spacing $d$ can be found using Bragg's Law: $n\lambda = 2d\sin\theta$. For the first-order maximum, $n = 1$. Rearranging gives $d = \frac{\lambda}{2\sin\theta}$. Substituting $\lambda = 0.500 \times 10^{-10} \, \text{m}$ and $\theta = 5.00^\circ$, we find $d = \frac{0.500 \times 10^{-10}}{2 \sin(5.00^\circ)} \approx 2.87 \times 10^{-10} \, \text{m}$.

In an X-Ray Diffraction Experiment Using X-Rays Of λ\lambdaλ = 0500 *10-10 M, a First-Order Maximum Occurred at 5

In an X-Ray Diffraction Experiment Using X-Rays Of $\lambda$ = 0500 *10-10 M, a First-Order Maximum Occurred at 5