Monochromatic light ($\lambda$ = 500 nm)is incident on a soap bubble (n = 1.4)that is 500-nm thick.Calculate the change of phase of the light that penetrates the front surface,reflects from the second surface,and emerges through the first surface as an angle between 0$\degree$ and 360$\degree$?
A)280$\degree$
B)160$\degree$
C)220$\degree$
D)100$\degree$
E)290$\degree$

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The Answer of Monochromatic light ($\lambda$ = 500 nm)is incident on a soap bubble (n = 1.4)that is 500-nm thick.Calculate the change of phase of the light that penetrates the front surface,reflects from the second surface,and emerges through the first surface as an angle between 0$\degree$ and 360$\degree$?
A)280$\degree$
B)160$\degree$
C)220$\degree$
D)100$\degree$
E)290$\degree$

Monochromatic Light λ\lambdaλ = 500 Nm)is Incident on a Soap Bubble (N =

Monochromatic Light $\lambda$ = 500 Nm)is Incident on a Soap Bubble (N =