A rectangular loop (area = 0.15 m2) turns in a uniform magnetic field with B = 0.20 T.At an instant when the angle between the magnetic field and the normal to the plane of the loop is ( $\pi$/2) rad and increasing at the rate of 0.60 rad/s, what is the magnitude of the emf induced in the loop?

Question

Quizplus · Accepted Answer

The induced emf in a rectangular loop of area A, rotated with an angular velocity ω in a uniform magnetic field of magnitude B is given by the equation:
emf = B*A*ω*cosθ
where θ is the angle between the normal to the plane of the loop and the magnetic field.

In this case, A = 0.15 m^2, B = 0.20 T, ω = 0.60 rad/s, and cos(π/4) = 1/√2.

Substituting these values, we get:
emf = 0.20 * 0.15 * 0.60 * 1/√2 = 0.018 V = 18 mV

Therefore, the correct answer is (C) 18 mV.

A Rectangular Loop (Area = 0 π\piπ /2) Rad and Increasing at the Rate of 0

A Rectangular Loop (Area = 0 $\pi$ /2) Rad and Increasing at the Rate of 0