A small airplane with a wing span of 12 m flies horizontally and due north at a speed of 60 m/s in a region where the magnetic field of the Earth is 60$\mu$T directed 60 $\degree$below the horizontal.What is the magnitude of the induced emf between the ends of the wing?

Question

Quizplus · Accepted Answer

The induced emf (ε) can be calculated using the formula ε = B * v * l * sin(θ), where B is the magnetic field strength, v is the velocity, l is the length of the wing, and θ is the angle between the magnetic field and the horizontal plane. Here, B = 60 μT = 60 x 10^-6 T, v = 60 m/s, l = 12 m, and θ = 60°. Therefore, ε = 60 x 10^-6 T * 60 m/s * 12 m * sin(60°) = 37 mV.

A Small Airplane with a Wing Span of 12 M μ\muμ

A Small Airplane with a Wing Span of 12 M $\mu$