A straight wire (length = 8.0 m) is bent to form a square.If the wire carries a current of 20 A, what is the magnitude of the magnetic field at the centre of the square?
A)17$\mu$T
B)14 $\mu$T
C)11 $\mu$T
D)20 $\mu$T
E)36 $\mu$T

Question

Quizplus · Accepted Answer

The magnetic field at the center of a square loop carrying current is given by $ B = \frac{2\sqrt{2}\mu_0 I}{\pi a} $, where $ a $ is the side of the square. Here, $ a = \frac{8}{4} = 2 $ m, and using $ \mu_0 = 4\pi \times 10^{-7} $ Tm/A, the calculation gives approximately 11 $\mu$T.

A Straight Wire (Length = 8 μ\muμ T B)14 μ\muμ T C)11 μ\muμ

A Straight Wire (Length = 8 $\mu$ T
B)14 $\mu$ T
C)11 $\mu$