A hollow cylindrical (inner radius = 2.0 mm, outer radius = 4.0 mm) conductor carries a current of 24 A parallel to its axis. This current is uniformly distributed over a cross section of the conductor. Determine the magnitude of the magnetic field at a point that is 5.0 mm from the axis of the conductor.
A) 0.96 mT
B) 1.7 mT
C) 0.55 mT
D) 1.2 mT
E) 0.40 mT

Question

Quizplus · Accepted Answer

The point is outside the conductor, so the magnetic field is calculated using Ampère's Law for a long straight conductor: B = (μ₀I)/(2πr). Substituting the given values, B = (4π × 10⁻⁷ T·m/A × 24 A)/(2π × 0.005 m) = 0.96 mT.

A Hollow Cylindrical (Inner Radius = 2