A 6.0-$\mu$F capacitor charged to 50 V and a 4.0-$\mu$F capacitor charged to 34 V are connected to each other, with the two positive plates connected and the two negative plates connected.What is the total energy stored in the 6.0-$\mu$F capacitor at equilibrium?
A)6.1 mJ
B)5.7 mJ
C)6.6 mJ
D)7.0 mJ
E)3.8 mJ

Question

Quizplus · Accepted Answer

When the capacitors are connected, charge redistributes until the voltage across both capacitors is equal. The total charge is conserved, and the final voltage can be found using the formula: $V_f = \frac{C_1V_1 + C_2V_2}{C_1 + C_2}$. The energy stored in the 6.0-$\mu$F capacitor at equilibrium is then calculated using $E = \frac{1}{2}C_1V_f^2$.

A 60- μ\muμ F Capacitor Charged to 50 V and a 4

A 60- $\mu$ F Capacitor Charged to 50 V and a 4