A point charge of 6.0 nC is placed at the centre of a hollow spherical conductor (inner radius = 1.0 cm, outer radius = 2.0 cm) which has a net charge of -4.0 nC.Determine the resulting charge density on the inner surface of the conducting sphere.
A)+4.8 $\mu$C/m2
B)(-4.8 $\mu$C/m2)
C)(-9.5 $\mu$C/m2)
D)+9.5$\mu$C/m2
E)(-8.0 $\mu$C/m2)

Question

Quizplus · Accepted Answer

The charge on the inner surface of the conductor must be -6.0 nC to cancel the electric field inside the conductor due to the point charge. The surface area of the inner surface is $4\pi(0.01)^2$ m². The charge density is $-6.0 \, \text{nC} / 4\pi(0.01)^2 \, \text{m}^2 = -4.8 \, \mu\text{C/m}^2$.

A Point Charge of 6 μ\muμ C/m2 B)(-4 μ\muμ C/m2) C)(-9 μ\muμ C/m2) D)+9

A Point Charge of 6 $\mu$ C/m2
B)(-4 $\mu$ C/m2)
C)(-9 $\mu$ C/m2)
D)+9