Gas in a container expands at a constant pressure of 3 atm. Find the work done (in J) by the gas if the initial volume is 5 litres and the final volume is 10 litres.

Question

Quizplus · Accepted Answer

The work done by the gas is given by the formula: 
W = PΔV 
where P is the constant pressure and ΔV is the change in volume. 
ΔV = Final volume - Initial volume = 10 L - 5 L = 5 L 
W = 3 atm x 5 L 
W = 15 L•atm or 15 J (since 1 atm•L = 1 J) 
Therefore, the answer is D) 1,500 J.

Gas in a Container Expands at a Constant Pressure of 3