Transverse waves y1 = A1 sin(k1x - $ \omega $1t) and y2 = A2 sin(k2x - $ \omega $2t), with A2 A1, start at opposite ends of a long rope when t = 0. The magnitude of the maximum displacement, y, of the rope at any point is:
A)A1 -A2.
B)A2- A1.
C)A1 + A2.
D) $\left(A_{1}-A_{2}\right) \frac{k_{1}}{k_{2}}$ .
E) $\left(A_{2}-A_{1}\right) \frac{k_{2}}{k_{1}}$ .

Question

Transverse waves y1 = A1 sin(k1x - $ \omega $1t) and y2 = A2 sin(k2x - $ \omega $2t), with A2 > A1, start at opposite ends of a long rope when t = 0. The magnitude of the maximum displacement, y, of the rope at any point is:
A)A1 -A2.
B)A2- A1.
C)A1 + A2.
D) $\left(A_{1}-A_{2}\right) \frac{k_{1}}{k_{2}}$ .
E) $\left(A_{2}-A_{1}\right) \frac{k_{2}}{k_{1}}$ .

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The Answer of Transverse waves y1 = A1 sin(k1x - $ \omega $1t) and y2 = A2 sin(k2x - $ \omega $2t), with A2 > A1, start at opposite ends of a long rope when t = 0. The magnitude of the maximum displacement, y, of the rope at any point is:
A)A1 -A2.
B)A2- A1.
C)A1 + A2.
D) $\left(A_{1}-A_{2}\right) \frac{k_{1}}{k_{2}}$ .
E) $\left(A_{2}-A_{1}\right) \frac{k_{2}}{k_{1}}$ .

Transverse Waves Y1 = A1 Sin(k1x - ω \omega ω 1t) and Y2 = A2 Sin(k2x -

Transverse Waves Y1 = A1 Sin(k1x - $\omega$ 1t) and Y2 = A2 Sin(k2x -