Write the equation of a wave, travelling along the +x axis with an amplitude of 0.02 m, a frequency of 440 Hz, and a speed of 330 m/sec.
A)y = 0.02 sin [880 $\pi$(x/330 -t)]
B)y = 0.02 cos [880 $\pi$ x/330 -440t]
C)y = 0.02 sin [880 $\pi$(x/330 + t)]
D)y = 0.02 sin [2 $\pi$(x/330 + 440t)]
E)y = 0.02 cos [2 $\pi$0(x/330 + 440t)]

Question

Quizplus · Accepted Answer

The wave equation is y = A sin(2π(ft - x/λ)), where A is amplitude, f is frequency, and λ is wavelength. Here, λ = v/f = 330/440 = 0.75 m. Thus, the equation becomes y = 0.02 sin[2π(440t - x/0.75)], which simplifies to y = 0.02 sin[880π(x/330 - t)].

Write the Equation of a Wave, Travelling Along the +X π\piπ

Write the Equation of a Wave, Travelling Along the +X $\pi$