Water is sent from a firehose at 30.0 m/s at an angle of 30.0 $\degree$ above the horizontal.What is the maximum height reached by the water?
A)7.50 m
B)11.5 m
C)15.0 m
D)19.0 m
E)30.0 m

Question

Quizplus · Accepted Answer

The vertical component of the velocity is $ v_y = 30.0 \, \text{m/s} \times \sin(30^\circ) = 15.0 \, \text{m/s} $. Using the formula for maximum height $ h = \frac{v_y^2}{2g} $, where $ g = 9.8 \, \text{m/s}^2 $, we get $ h = \frac{(15.0)^2}{2 \times 9.8} = 11.5 \, \text{m} $.

Water Is Sent from a Firehose at 30 °\degree° Above the Horizontal

Water Is Sent from a Firehose at 30 $\degree$ Above the Horizontal