What is the kinetic energy of a 200-kg satellite as it follows a circular orbit of radius 8.0 *106 m around the Earth? (Mass of Earth = 6.0 * 1024 kg.)
A)5.0 *109 J
B)1.0 * 1010 J
C)1.5 * 1010 J
D)2.0 * 1010 J
E)2.5 * 109 J

Question

Quizplus · Accepted Answer

Kinetic energy = 1/2 mv^2 = 1/2 * 200 kg * (v)^2v = sqrt(GM/r) = sqrt((6.67 * 10^-11 N m^2 / kg^2 * 6.0 * 10^24 kg) / (8.0 * 10^6 m)) = 7900 m/sKinetic energy = 1/2 * 200 kg * (7900 m/s)^2 = 5.0 * 10^9 J

What Is the Kinetic Energy of a 200-Kg Satellite as It