Refer to Exhibit 9-2 below.Exhibit 9-2 The figure below shows a graph of angular velocity versus time for a man cycling around a circular track. What is his average angular acceleration, in rad/s2, in the first 10 minutes?
A)0
B) $-\frac{\pi}{150}$
C) $-\frac{\pi}{75}$
D) $+\frac{\pi}{75}$
E) $+\frac{\pi}{150}$

Question

Refer to Exhibit 9-2 below.Exhibit 9-2 The figure below shows a graph of angular velocity versus time for a man cycling around a circular track.  What is his average angular acceleration, in rad/s2, in the first 10 minutes?
A)0 
B) $-\frac{\pi}{150}$ 
C) $-\frac{\pi}{75}$ 
D) $+\frac{\pi}{75}$ 
E) $+\frac{\pi}{150}$

Quizplus · Accepted Answer

The average angular acceleration can be calculated by taking the change in angular velocity over the change in time. From the graph, we can see that the angular velocity remains constant at 1 rad/s for the first 10 minutes (600 seconds), so the change in angular velocity is 0. Therefore, the average angular acceleration is 0 rad/s^2. Choice A is incorrect because the man is technically accelerating as he goes around the circular track, but his average angular acceleration for the first 10 minutes is still 0. Choices B, D, and E are incorrect because they all suggest a non-zero average angular acceleration, which is not the case for the first 10 minutes according to the graph.

Refer to Exhibit 9-2 Below −π150-\frac{\pi}{150}−150π​ C) −π75-\frac{\pi}{75}−75π​ D) +π75+\frac{\pi}{75}+75π​ E) +π150+\frac{\pi}{150}+150π​

Refer to Exhibit 9-2 Below $-\frac{\pi}{150}$ C) $-\frac{\pi}{75}$ D) $+\frac{\pi}{75}$ E) $+\frac{\pi}{150}$