A 3.0-kg block slides on a rough horizontal surface. A force of 8.0 N acting parallel to the surface is applied to the block. The coefficient of kinetic friction between the block and the surface is 0.15. What is the magnitude of the block's acceleration?
A)1.9 m/s2
B)1.2 m/s2
C)2.3 m/s2
D)1.5 m/s2
E)2.9 m/s2

Question

Quizplus · Accepted Answer

The net force is the applied force minus the frictional force. Frictional force = coefficient of friction * normal force = 0.15 * 3.0 kg * 9.8 m/s² = 4.41 N. Net force = 8.0 N - 4.41 N = 3.59 N. Acceleration = net force / mass = 3.59 N / 3.0 kg = 1.2 m/s².

A 30-Kg Block Slides on a Rough Horizontal Surface