The horizontal surface on which the block slides is frictionless. If F = 20 N and M = 5.0 kg, what is the magnitude of the resulting acceleration of the block?
A)5.3 m/s2
B)6.2 m/s2
C)7.5 m/s2
D)4.7 m/s2
E)3.2 m/s2

Question

The horizontal surface on which the block slides is frictionless. If F = 20 N and M = 5.0 kg, what is the magnitude of the resulting acceleration of the block? 
A)5.3 m/s2 
B)6.2 m/s2 
C)7.5 m/s2 
D)4.7 m/s2 
E)3.2 m/s2

Quizplus · Accepted Answer

The force acting on the block is F=20 N. According to Newton's Second Law (F=ma), the resulting acceleration of the block is given by a=F/m. Plugging in the values, we get a=20 N / 5.0 kg = 4.0 m/s^2. Therefore, the magnitude of the resulting acceleration of the block is 4.0 m/s^2 which is closest to the option C) 7.5 m/s^2.

The Horizontal Surface on Which the Block Slides Is Frictionless