A 70-kg stunt artist rides in a rocket sled which slides along a flat inclined surface. At an instant when the sled's acceleration has a horizontal component of 6.0 m/s2 and a downward component of 2.8 m/s2, what is the magnitude of the force on the rider by the sled?
A)0.83 kN
B)0.98 kN
C)0.65 kN
D)0.68 kN
E)0.72 kN

Question

Quizplus · Accepted Answer

We can use Newton's second law to solve for the force on the rider by the sled: 
F = ma 
where F is the force, m is the mass of the rider, and a is the acceleration of the sled.

We need to first find the total acceleration of the sled, which can be found using the Pythagorean theorem: 
a = sqrt((6.0 m/s^2)^2 + (2.8 m/s^2)^2) 
a = 6.44 m/s^2

Now we can solve for the force using Newton's second law: 
F = ma 
F = (70 kg)(6.44 m/s^2) 
F = 449.8 N

Converting to kN gives: 
F = 0.45 kN

Therefore, the closest answer choice is C: 0.65 kN.

A 70-Kg Stunt Artist Rides in a Rocket Sled Which