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Question 38
Solve the differential equation. yt=x(1+y) y ^ { t } = x ( 1 + y ) yt=x(1+y)
A) ln∣1+y∣=x2+C\ln | 1 + y | = x ^ { 2 } + Cln∣1+y∣=x2+C B) \3ln∣1+y∣=x3+C\3 \ln | 1 + y | = x ^ { 3 } + C\3ln∣1+y∣=x3+C C) 4ln∣1+y∣=x4+C4 \ln | 1 + y | = x ^ { 4 } + C4ln∣1+y∣=x4+C D) ln∣1+y∣=x+C\ln | 1 + y | = x + Cln∣1+y∣=x+C E) 2ln∣1+y∣=x2+C2 \ln | 1 + y | = x ^ { 2 } + C2ln∣1+y∣=x2+C
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