Neglecting air resistance and the weight of the propellant, determine the work done in propelling a six-ton satellite to a height of 200 miles above earth. Assume that Earth has a radius of 4000 miles.
A) $5.07 \times 10 ^ { 10 } \mathrm { ft } - \mathrm { lb }$
B) $6.03 \times 10 ^ { 9 } \mathrm { ft } - \mathrm { lb }$
C) $1.21 \times 10 ^ { 12 } \mathrm { ft } - \mathrm { b }$
D) $1.21 \times 10 ^ { 10 } \mathrm { ft } - \mathrm { lb }$
E) $5.07 \times 10 ^ { 12 } \mathrm { ft } - \mathrm { lb }$

Question

Neglecting air resistance and the weight of the propellant, determine the work done in propelling a six-ton satellite to a height of 200 miles above earth. Assume that Earth has a radius of 4000 miles. 
A) $5.07 \times 10 ^ { 10 } \mathrm { ft } - \mathrm { lb }$
B) $6.03 \times 10 ^ { 9 } \mathrm { ft } - \mathrm { lb }$
C) $1.21 \times 10 ^ { 12 } \mathrm { ft } - \mathrm { b }$
D) $1.21 \times 10 ^ { 10 } \mathrm { ft } - \mathrm { lb }$
E) $5.07 \times 10 ^ { 12 } \mathrm { ft } - \mathrm { lb }$

Quizplus · Accepted Answer

The Answer of Neglecting air resistance and the weight of the propellant, determine the work done in propelling a six-ton satellite to a height of 200 miles above earth. Assume that Earth has a radius of 4000 miles. 
A) $5.07 \times 10 ^ { 10 } \mathrm { ft } - \mathrm { lb }$
B) $6.03 \times 10 ^ { 9 } \mathrm { ft } - \mathrm { lb }$
C) $1.21 \times 10 ^ { 12 } \mathrm { ft } - \mathrm { b }$
D) $1.21 \times 10 ^ { 10 } \mathrm { ft } - \mathrm { lb }$
E) $5.07 \times 10 ^ { 12 } \mathrm { ft } - \mathrm { lb }$

Neglecting Air Resistance and the Weight of the Propellant, Determine 5.07×1010ft−lb5.07 \times 10 ^ { 10 } \mathrm { ft } - \mathrm { lb }5.07×1010ft−lb

Neglecting Air Resistance and the Weight of the Propellant, Determine $5.07 \times 10 ^ { 10 } \mathrm { ft } - \mathrm { lb }$