Solve the inequality. $\frac { 18 ( x - 8 ) } { 5 } \geq \frac { 9 ( x + 4 ) } { 4 }$
A) none of the above
B) $\quad ( 28 , \infty )$
C) $[ - 28 , \infty )$
D) $\quad ( - 28 , \infty )$
E) $[ 28 , \infty )$

Question

Quizplus · Accepted Answer

To solve the inequality, first clear the fractions by multiplying both sides by 20 (the least common multiple of 5 and 4). This gives: $72(x - 8) \geq 45(x + 4)$. Simplifying, we get: $72x - 576 \geq 45x + 180$. Subtract 45x from both sides: $27x - 576 \geq 180$. Add 576 to both sides: $27x \geq 756$. Divide by 27: $x \geq 28$. Therefore, the solution is $[28, \infty)$.

Solve the Inequality 18(x−8)5≥9(x+4)4\frac { 18 ( x - 8 ) } { 5 } \geq \frac { 9 ( x + 4 ) } { 4 }518(x−8)​≥49(x+4)​

Solve the Inequality $\frac { 18 ( x - 8 ) } { 5 } \geq \frac { 9 ( x + 4 ) } { 4 }$