A boy on board a cruise ship drops a 30.0 g marble into the ocean. If the resistive force proportionality constant is 0.500 kg/s, what is the terminal speed of the marble in m/s?

Question

Quizplus · Accepted Answer

We can start with the formula for terminal velocity:

v = mg/k

where 
m = mass of the marble = 30.0 g = 0.03 kg
g = acceleration due to gravity = 9.81 m/s^2 (assuming near the Earth's surface)
k = resistive force proportionality constant = 0.500 kg/s

Plugging in the values:

v = (0.03 kg)(9.81 m/s^2)/(0.500 kg/s) = 0.588 m/s

Therefore, the terminal speed of the marble is 0.588 m/s, or choice C.

A Boy on Board a Cruise Ship Drops a 30