A stunt pilot performs a circular dive of radius 800 m. At the bottom of the dive (point B in the figure) the pilot has a speed of 200 m/s which at that instant is increasing at a rate of 20 m/s². What acceleration does the pilot have at point B? A) m/s² B) m/s² C) m/s² D) m/s² E) m/s²

Question

Quizplus · Accepted Answer

The acceleration of the pilot at point B can be found using the equation:
a = v^2/R + dv/dt
where
v = 200 m/s (speed at point B)
R = 800 m (radius of the circular dive)
dv/dt = 20 m/s^2 (rate of increase of speed at point B)
Substituting these values, we get:
a = (200 m/s)^2/800 m + 20 m/s^2
a = 50 m/s^2 + 20 m/s^2
a = 70 m/s^2
Therefore, the acceleration of the pilot at point B is 70 m/s^2, which is closest to option C (11eb8c7e_f557_50ae_8371_e152b99b0a3e_TB8847_11 m/s^2).

A Stunt Pilot Performs a Circular Dive of Radius 800