A 60.0-Hz AC generator with a peak voltage of 110 V drives a series RC circuit with R = 10.0 Ω and C = 300 μF. The impedance is
A)4.68 Ω.
B)8.84 Ω.
C)10.0 Ω.
D)13.4 Ω.
E)18.8 Ω.

Question

Quizplus · Accepted Answer

The impedance Z of a series RC circuit is given by $ Z = \sqrt{R^2 + (X_C)^2} $, where $ X_C = \frac{1}{2\pi f C} $ is the capacitive reactance. For the given values, $ X_C = \frac{1}{2\pi \times 60 \times 300 \times 10^{-6}} \approx 8.84 \, \Omega $. Thus, $ Z = \sqrt{10^2 + 8.84^2} \approx 13.4 \, \Omega $.

A 600-Hz AC Generator with a Peak Voltage of 110 V