A metal blade (length = 80 cm) spins at a constant rate of 10 radians/s about a pivot at one end. A uniform magnetic field of 2.0 mT is directed at an angle of 30° with the plane of the rotation. What is the magnitude of the potential difference between the two ends of the blade?

Question

Quizplus · Accepted Answer

The potential difference (emf) induced in the blade can be calculated using the formula: emf = (1/2) * B * ω * L² * sin(θ), where B is the magnetic field, ω is the angular velocity, L is the length of the blade, and θ is the angle between the magnetic field and the plane of rotation. Substituting the given values: B = 2.0 mT = 2.0 x 10⁻³ T, ω = 10 rad/s, L = 0.8 m, and θ = 30°, we get emf = (1/2) * 2.0 x 10⁻³ * 10 * (0.8)² * sin(30°) = 3.2 mV.

A Metal Blade (Length = 80 Cm) Spins at a Constant