A charged particle (mass = m, charge = q 0) moves in a region of space where the magnetic field has a constant magnitude of B and a downward direction. What is the magnetic force on the particle at an instant when it is moving horizontally toward the north with speed v?
A)qvB toward the east
B)Zero
C)qvB toward the west
D)qvB upward
E)qvB toward the south

Question

A charged particle (mass = m, charge = q > 0) moves in a region of space where the magnetic field has a constant magnitude of B and a downward direction. What is the magnetic force on the particle at an instant when it is moving horizontally toward the north with speed v?
A)qvB toward the east
B)Zero
C)qvB toward the west
D)qvB upward
E)qvB toward the south

Quizplus · Accepted Answer

The magnetic force on a moving charged particle is given by the formula F = qvBsinθ, where θ is the angle between the velocity vector and the magnetic field vector. In this case, the particle is moving horizontally towards the north, so its velocity vector is pointing towards the west. Since the magnetic field is pointing downwards, the angle between the velocity vector and the magnetic field vector is 90 degrees. Therefore sinθ = 1, and the magnetic force is F = qvBsinθ = qvB, pointing towards the west.

A Charged Particle (Mass = M, Charge = Q >