Determine the energy stored in the 60-μF capacitor.

Question

Quizplus · Accepted Answer

The energy stored in a capacitor is given by the formula:

E = 1/2*C*V^2

where E is energy, C is capacitance, and V is the voltage across the capacitor.

In this problem, the capacitance is given as 60 μF. We are not given the voltage across the capacitor directly, but we can determine it using the information provided.

We know that the 10 μF capacitor is charged to 80 V, and then connected in parallel with the 60 μF capacitor. When capacitors are connected in parallel, the voltage across each capacitor is the same. Therefore, the voltage across the 60 μF capacitor is also 80 V.

Plugging in the values, we get:

E = 1/2*(60*10^-6)*(80)^2
E = 3.0*10^-3 J

Converting to millijoules (mJ), we get:

E = 3.0 mJ, which is the closest answer choice.

Determine the Energy Stored in the 60-μF Capacitor