What is the speed of a proton that has been accelerated from rest through a potential difference of 4.0 kV?

Question

Quizplus · Accepted Answer

The kinetic energy gained by the proton is equal to the work done on it by the electric field, which is the charge of the proton multiplied by the potential difference. Using the formula $ KE = \frac{1}{2}mv^2 = qV $, where $ q = 1.6 \times 10^{-19} $ C, $ V = 4.0 \times 10^3 $ V, and $ m = 1.67 \times 10^{-27} $ kg, solving for $ v $ gives approximately $ 8.8 \times 10^5 $ m/s.

What Is the Speed of a Proton That Has Been