Two concentric imaginary spherical surfaces of radius R and 2R, respectively, surround a positive point charge Q located at the center of the surfaces. When compared to the electric flux Φ1 through the surface of radius R, the electric flux Φ2 through the surface of radius 2R is

Question

Quizplus · Accepted Answer

The electric flux through the two surfaces is given by the equation Φ = Q/ε₀, where Q is the charge enclosed by the surface and ε₀ is the permittivity of free space. Since the charge Q is located at the center of the two surfaces, it is enclosed by both surfaces. Therefore, the charge enclosed and ε₀ are the same for both surfaces, which means that the electric flux through the two surfaces is also the same. Thus, Φ2 = Φ1.

Two Concentric Imaginary Spherical Surfaces of Radius R and 2R