How large a force is necessary to stretch a 2.0-mm diameter copper wire (Y = 11 × 10¹⁰ N/m²) by 1.0%?

Name: How large a force is necessary to stretch a 2.0-mm diameter copper wire (Y = 11 × 10 10 N/m 2 ) by 1.0%?
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Quizplus · Accepted Answer

To find the force, use the formula for Young's modulus: Y = (F/A) / (ΔL/L). Here, Y = 11 × 10^10 N/m², ΔL/L = 0.01 (1% stretch), and the cross-sectional area A = π(d/2)² = π(0.001 m)². Solving for F gives approximately 3.5 kN.

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