Solve the logarithmic equation below algebraically.
$$\log _ { 6 } ( 2 x + 4 ) = \log _ { 6 } ( 5 x + 1 )$$
A) 3
B) $- 2$
C) $- 4$
D) 2
E) 1

Name: Solve the logarithmic equation below algebraically. \[\log _ { 6 } ( 2 x + 4 ) = \log _ { 6 } ( 5 x + 1 )\] A) 3 B) $- 2$ C) $- 4$ D) 2 E) 1
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The Answer of Solve the logarithmic equation below algebraically.
$$\log _ { 6 } ( 2 x + 4 ) = \log _ { 6 } ( 5 x + 1 )$$
A) 3
B) $- 2$
C) $- 4$
D) 2
E) 1

Solve the Logarithmic Equation Below Algebraically log⁡6(2x+4)=log⁡6(5x+1)\log _ { 6 } ( 2 x + 4 ) = \log _ { 6 } ( 5 x + 1 )log6​(2x+4)=log6​(5x+1)

Solve the Logarithmic Equation Below Algebraically $\log _ { 6 } ( 2 x + 4 ) = \log _ { 6 } ( 5 x + 1 )$